Electrical mathQuestion 1367 of 1506

A 12 kW heater runs 3 hours each day for 7 days. How much energy does it use?

  1. 252 kWh
  2. 126 kWh
  3. 84.0 kWh
  4. 21.0 kWh
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Correct answer: 252 kWh

Energy = power × time = 12 kW × 3 h × 7 days = 252 kWh.

Source: Computed, 12.3: Power Measurement

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Questions last reviewed: 18 October 2026