Magnetism and electromagnetismQuestion 877 of 1506

A coil has 500 turns. The flux through it changes at a rate of 0.02 Wb per second. What voltage is induced in the coil?

0.02 V
10 V
1 V
25,000 V

Show answer

Correct answer: 10 V

Faraday’s law: e = N × (rate of change of flux) = 500 × 0.02 = 10 V.

Source: Lessons in Electric Circuits I: DC (Kuphaldt), 14.5: Electromagnetic Induction

Questions last reviewed: 18 October 2026

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