DC circuitsQuestion 646 of 1506

A 12 V source feeds a 6 Ω and a 12 Ω resistor in parallel. What is the total power dissipated?

  1. 36 W
  2. 8 W
  3. 24 W
  4. 72 W
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Correct answer: 36 W

P = 144/6 + 144/12 = 24 W + 12 W = 36 W. The total power is the sum of the individual powers.

Source: Lessons in Electric Circuits I: DC (Kuphaldt), 5.5: Power Calculations

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Questions last reviewed: 18 October 2026