Red Seal Electrician Practice
Magnetism and electromagnetismQuestion 509 of 1506

A conductor with an active length of 4 m moves at 15 m/s through a 5 T field. What is the peak induced voltage?

  1. 75 V
  2. 24 V
  3. 300 V
  4. 20 V
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Correct answer: 300 V

e = B x l x v = 5 T x 4 m x 15 m/s = 300 V.

Source: Trigonometry and Single Phase AC Generation for Electricians (Flinn), 3.1: Electromagnetic Induction

Practice magnetism and electromagnetism

Questions last reviewed: 18 October 2026