AC generationQuestion 160 of 1506

A conductor with an active length of 3 m moves through a 1.4 T field and a peak of 42 V is induced. How fast does it move?

  1. 30 m/s
  2. 176 m/s
  3. 10 m/s
  4. 0.1 m/s
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Correct answer: 10 m/s

v = e ÷ (B × l) = 42 ÷ (1.4 × 3) = 10 m/s.

Source: Trigonometry and Single Phase AC Generation for Electricians (Flinn), 3.1: Electromagnetic Induction

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Questions last reviewed: 18 October 2026